Hardness water lab help please fill in the blanks thank you. will thumb up answe
ID: 495646 • Letter: H
Question
Hardness water lab help
please fill in the blanks thank you. will thumb up answers.
Part A: Preparation of Calcium Carbonate Standard a) Mass of calcium carbonate b) Total volume of standard solution c) Molarity of calcium carbonate standard Part B: Determination of Blank Volume Trial 1 Trial 2 Trial 3 1aas Final Burette Reading (mL) Initial Burette Reading (mL) 5. 0,30 30 Volume for Blank (mL) Average Blank: LOO t Part C: Standardization of EDTA Titration Trial 1 Trial 2 Trial 3 Final Burette Reading (mL) Initial Burette Reading (mL) o 00 13 50 24ioo Volume for EDTA (mL) LOO Average Volume of Blank (mL) Volume of EDTA used to titrate Ca lilo ,8 I, 88 Molarity of EDTA (show calcs) Awrage Molarity of EDTA (show calc): 134 SM t eia3 (M)Explanation / Answer
Moles of EDTA required to titrate 25mL unknown sample :
Trial 1 : 1.845 M 0.005 L= 9.23*10^-3 moles
trial 2 : 1.845 M * 0.0052 L= 9.59*10^-3 moles
Trial 3 : 1.845 M * 0.0053 L = 9.78*106-3 moles
---------------------------------------------------
moles of caCO3 / 25mL of unknown solution
Trial 1 : 9.23*10^-3 moles
trial 2 : 9.59*10^-3 moles
Trial 3 : 9.78*106-3 moles
---------------------------------------------------
weight of caCO3 per 25mL solution
Trial 1 : 100g/mol * 9.23*10^-3 moles = 0.923 gm
trial 2 : 100g/mol * 9.59*10^-3 moles = 0.959 gm
Trial 3 : 100g/mol * 9.78*106-3 moles = 0.978 gm
---------------------------------------------------
weight od CaCO3 in 10^6 mL solution
Trial 1 : 0.923 gm *10^6/25mL = 36.92 *10^3 gm
trial 2 : 0.959 gm *10^6/25mL = 38.36*10^3 gm
Trial 3 : 0.978 gm * *10^6/25mL = 39.12*10^3 gm
--------------------------------------------------------
1 ppm = 1mg/L
trial 1 : 36.92 *10^3 gm / 10^6 mL
= 36.92 *10^3 ppm
Trial 2 : 38.36 *10^3 ppm
Trial 3 : 39.12 *10^3 ppm
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.