C6H7N aniline MW = 93.13 g/mol Density = 1.022 g/mL C4H6O3 acetic anhydride MW =

Question

C6H7N aniline MW = 93.13 g/mol Density = 1.022 g/mL
C4H6O3 acetic anhydride MW = 102.09 g/mol Density = 1.087 g/mL
C8H9NO acetanilide MW = 135.16 g/mol Density = 1.121 g/mL
1 mL of aniline was used with acetic anhydride in a 1 to 1.2 ratio.
Find the limiting reagent and theoretical yield for acetanilide product.
*Please show the work. I've been working on this question for a long time and I have two different answers and am getting more confused. Thank you!! Exper mental A. Reachon. epl Step e Reagent tabte step 1 and 2 UATORP CAS 08.13 loa ,ea mass gimti 9 Imol gimol mol glmol Ratio 1.2 1 S I 1.022 1.021 12 1.753 Denon mL HAYDEN-McNEIL, STUDENT LAB NOTEB00K

Explanation / Answer

1 mL of aniline was used with acetic anhydride in a 1 to 1.2 ratio.so volume of acetic anhydride is 1.2 mL

from balence chemical reaction between aniline and acetic anhydride 1 mole of aniline react with 1 mole of acetic anhydride.

mass of aniline = density x volume

mass = 1.022 g/mL x 1 mL = 1.022 g

moles of aniline = mass / molar mass = 1.022 g / 93.13 g/mol = 0.010974 moles

mass of acetic anhydride = 1.2 mL x 1.087 g/mL = 1.3044 g

moles of acetic anhydride = 1.3044 g / 102.09 g/mol =0.012777 moles

ratio of reactant is 1:1

so aniline is limiting reagent

moles of acetanilide = 0.010974 moles

mass of acetanilide = 0.010974 moles x 135.16 g/mol = 1.483 g

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