15. originally a flask contains Heat150 mmHg The contents of a second flask, O.

Question

15. originally a flask contains Heat150 mmHg The contents of a second flask, O. at 600 mmHg are forced into the flask containing He. What is the resulting pressure in the flask? a. 150 mmHg b. 600 mmHg 750 mmHg d. 1350 mmHg the bottle is placed in water at 75 c, what is the pressure in the bottle? 17. (6) A dilute solution is by transferring 45.00 mL of a 0.5616 M stock solution to a a prepared ofthis dilute 0.4000 L volumetric flask and diluting to mark. What is the molarity o solution? 18. According to the following thermochemical equation, if 951.1 g ofNO: is produced, how much heat is released at constant pressure? 2NO0g) O 2(g) 2NO20g); AH 114.4 kJ

Explanation / Answer

Total pressure Pt = Pa + Pb + ..,

Total pressure Pt = 150 mmHg + 600 mmHg = 750 mmHg Answer

Given

P1 = 744 mmHg V1 = 2 L T1 = 24 C = 297 K

Volume of bottle remains the same hence when temperature changes there will be change in pressure

T2 = 75 C = 348 K

assuming ideal gas law PV = nRT

P1* V1 = n * R * T1

P2 * V2 = n * R * T2

dividing both and V1 = V2 so

P1 / P2= T1/ T2

744 / P2 = 297 / 348

P2 = 871.76 mmHg Answer

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