General Chemistry Section 7 Herczogh Manipulating Theoretical. Actual, and Peroe
ID: 494998 • Letter: G
Question
General Chemistry Section 7 Herczogh Manipulating Theoretical. Actual, and Peroent Yields The mass product produced assuring a too Eyeais called the theoretical Part B A chemist anthe neachen and 54 g of What the percent Express your answer as a percent tothree significant figures. percent 58.7 Incorrect: Try Again: 4 attempts remaining The chemst discovers amore encert calaystthat can produce ethylbutyate wth a 780% yeld How many grams would be produced tom 805 gofbutanoc aod and excess emanon Express your answer in grams to three significant gures mass of ethy butyale OExplanation / Answer
The reaction is
C3H7COOH + C2H5OH -------> C3H7COOC2H5 + H2O
Maass of butanoic acid = 8.05
moles of butanoic acid = 8.05/88
=0.09147
part B )
According to equation 1 mole of acid gves one mole of product ester.
Thus 0.09147 mol of acid gives 0.09147 omoles of ester
Thus mass of ester theroretically = moles x molar mass
= 0.09147molx116 g/mol
= 10.61 g
experimental yield of product =5.45 g
Thus % yield= 5.45x100/10.61
= 51.36 %
part C
With the new catalyst the % yield is78.0%
Thu s the amount of product = 10.61x78/100
= 8.275 g
Thus the amount of product ester that will be produced from 8.05 g of acid = 8.275g
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