The generic reaction has the following rate laws: forward reaction: rate = k_f [

Question

The generic reaction has the following rate laws: forward reaction: rate = k_f [A]^2 reverse reaction: rate = k_r [B] where k_f is the rate constant for the forward reaction and is the rate constant for the reverse reaction. At equilibrium, the two rates are equal and so k_f [A]^2 = k_r [B]. the equilibrium constant for a reaction is related by the law of mass action to the rate constants for the forward and reverse reactions: Nitrosyl bromide. NOBr. is formed in the reaction of nitric oxide? NO. with bromine, Br2: the reaction rapidly establishes equilibrium when the reactants are mixed. At a certain temperature, the initial concentration of NO was 0.400 M and that of Bro was 0.255 M. At equilibrium, the concentration of NOBr was found to be 0.250 M. What is the value of Kc at this temperature? At this temperature, the rate constant for the reverse reaction is 320. AT1 s 1. What is kf for the reaction? Express your answer to three significant figures and include the appropriate units. Include an asterisk to indicate multiplication in compound units, for example to write the units for a second order rate constant type M^-1*s^-1.

Explanation / Answer

Given KC = 21.4

We know KC = Kf/kb

So, Kf = KC*Kb = 21.4*320 = 68.5*10^2

Units are M-1s-1

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