what concentration of zinc chloride solution is produced when 0.5065g of zinc is

Question

what concentration of zinc chloride solution is produced when 0.5065g of zinc is reacted with 100.0mL of 0.1260 M hydrochloric acid. Assume the total volume of the solutions is 100.0mL what concentration of zinc chloride solution is produced when 0.5065g of zinc is reacted with 100.0mL of 0.1260 M hydrochloric acid. Assume the total volume of the solutions is 100.0mL what concentration of zinc chloride solution is produced when 0.5065g of zinc is reacted with 100.0mL of 0.1260 M hydrochloric acid. Assume the total volume of the solutions is 100.0mL

Explanation / Answer

Zn(s) + 2HCl(aq)--------> ZnCl2(aq) + H2(g)

0.1260M HCl = 0.1260 mole HCl in 1000ml

So, in 1000ml no of mole of HCl = 0.0126 mole

Molar mass of Zn = 65.38g/mole

Mass of Zn = 0.5065g

no of moles of Zinc = mass/molar mass = 0.5065/65.38 = 0.00775mole

1mole of Zn require 2 mole of HCl

0.00775 mole of Zn require 0.0155 mole of HCl but actual mole of HCl is 0.0126. So , HCl is limiting and Zn is excess

2 mole of HCl give 1 mole of ZnCl2

0.0126 mole of HCl give 0.0063 mole of ZnCl2

0.0063 mole of ZnCl2 in 100ml

Therefore, Concentration of ZnCl2 = (0.0063mole/100ml)×1000ml = 0.063M

Therefore, concentration of ZnCl2 = 0.063M

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