1. The relation between gram and amu is represented by _________________________
ID: 494293 • Letter: 1
Question
1. The relation between gram and amu is represented by ____________________________(use NA = 6 x 10*23)
2. The atomic mass of Rubidium is 85, so the mass of one mole of Rubidium is______________________.
3. The atomic mass of silver (Ag) is 108. find the mass of two moles of silver atoms.___________________
4. The atomic mass of lithium (Li) is 7. the mass of one atom of lithium is ________________________.
5. Given the following atomic masses: N=14; O=16. tha is the molecular mass of N2O5?_______________________________
6. (Given: atomic masses of H=1; O =16;and S=32) The mass of one mole of sulphuric acid, H2SO4, is______________________________
7. Given the following atomic masses; N=14; O=16. What is the molar mass of N2O2?__________________________________________
8. How many moles are there in 3.9g of K? [Atomic mass of K=39]________________________________
9. Find the number of moles in 51 g of ammonia gas (NH3). [N=14; H=1]________________________
10. How many moles are present in 6.3 g of nitric acid HNO3? [Given atomic mass of H=1, N=14 and Q=16]
11. How many moles are contained in 620g of pure H2CO3? [Given atomic masses: H=1,C=12 and O=16]________________________
Explanation / Answer
1. 1 gram= 6.022*1023 amu
2. mass of 1 mole rubidium= 85.4678 grams
3.mass of two mole of Ag= 216 g
4.moles= mass/atomic mass, so 1= mass/7
= mass= 7g
5. N2O5 molecular mass= 2*14+5*16= 108 g/mol
6. mass of one mole of H2SO4 = 2*1+32 +4*16 = 98 g
7.molar mass of N2O2 = 2*14+2*16 = 60 g/mol
8. moles= weight/ molecualr weight
= 3.9/39= 0.1 moles
9. NH3 molecular weight= 14+3*1.008= 17.031 g/mol
number of moles= wt/mw = 51/ 17.031= 3 moles
10. moelcular weight of HNO3 = 63.01 g/mol
number of moles = 6.3/63.01= 0.1 moles
11. H2CO3 molecular weight = 62.03 g/mol ( 2*1+12+3*16=62.03)
number of mole s= 620/62.03 = 10 moles
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