Q: Please help answer question . The rest of the questions help give background.

Question

Q:
Please help answer question . The rest of the questions help give background.

1) Given that Al burned in excess oxygen releases 31.1 kJ/g, how many kJ were released during combustion of your Al sample?-->sample of Al was 8.890 g so I mulipled 31.1 kj/1 g times 8.890 g=276.5 Kj

2) what is the value of the temperature difference, tmax-tinitial, for the calibration run using al metal? 575.5-20.9=554.6

3) using the measured temperature change of the calibration run with Al, and the Kj of heat generated that you computed above, what is the response factor of the calorimeter in c/kj? 554.6/276.5=2

4) determine the energy released by combustion of the unknown organic compound. enter below the measured temperature change, tmax-tinitial for your data set unknown. 208-21.1=186.9

****question I need help with**** 5) With the response factor of the calorimeter that you calculated, and the measured temperature change for the unknown run, calculate the heat (in Kj) released during the combustion of the unknown. answer will be in kJ

Explanation / Answer

response factor = temperature change/ heat released

or, 2 = 186.9oC/ heat released

or, heat released = 186.9oC/2 = 93.45 kJ

So, combustion of the unknown release 93.45 kJ of heat.

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