Which of the following reacts fastest with NaOH in ethanol by S_N2 mechanism. Wh

Question

Which of the following reacts fastest with NaOH in ethanol by S_N2 mechanism. Which of the following reagent(s) can be used to prepare benzoic acid (Ph-CO_2H) from toluene? Fe/H_2SO_4 CH_3COOH KMnO_4 NBS/H_2O HNO_3/H_2SO_4 Intermediate in the S_N1 mechanism is a carbonium ion free-radical carbanion carbon with 5-bonds a primary carbon Transition state in the S_N2 mechanism is a primary carbon free-radical carbonium ion carbon with 5-bonds carbanion Which of the following reagent(s) gives the reaction below CH_3Br HBr Br_2/CCl_4 NBs/CCl_4 CH_3Br/FeBr_3 Formula of aniline is: C_6H_5OH C_6H_5NH C_6H_5NH_2 C_6H_5NH_3 C_6H_5NO_2 The rate of S_N1 reaction is proportional to: Base concentration RX concentration Nucleophile concentration RX and Nucleophile concentrations leaving group concentration The most likely mechanism for the reaction: CH_3CH_2-Br CH_2 = CH_2 S_N1 S_N2 E1 E2 E1_CB An allowed number of pi electrons for an aromatic compound is: 2 5 8 12 16 Which of the following is the best leaving group? F- Cl- Br- I- -OH Which of the following reacts fastest with NaOH in water by S_N1 mechanism. CH_3CI CH_3 Br CH_3CH_2CH_2Br (CH_3)_2CHBr (CH_3)_3CBr Which of the following is the best solvent for S_N1 mechanism? CH_3OH CHCl_3 CH_3CH_2CH_2OH H_2O CH_2Cl_2 Which of the following reagent(s) can be used to prepare toluene from benzene CH_3Cl/NBS CH_3Br/FeBr_3 H_2SO_4/CH_3Cl CH_3Cl/AlCl_3 CH_3Cl/light Which of the following functional groups are o, p-directing? NO_2, CH_3, OH Cl, NH_2, COOH I, SO, H, OH OCH_3, Cl, COCH_3 Br, CH_2CH_3, NH_2 Which of the following is the electrophile in the Friedel-Craft acylation reaction RCO^+ RCO_2^+ CO_2^+ RX/H_2SO_4 RCO_3^+

Explanation / Answer

1. answer is c) CH3I

2. answer is c) KMnO4

Explanation: KMnO4 is the strong oxidising reagent which converts toluene to benzoic acid

3. answer is a)

Explanation: More crowded alkyl halides undergo SN1 reaction. In a polar Solvent, it breaks to form a trigonal and sp2 hybridised, planar carbonium ion intermediate which is stabilized.

4. answer is c)

Explanation: The C - atom of the substrate molecule is sp3 hybridised and has tetrahedral shape with bond angle 109°28'. The +vely charged carbon is likely to be attacked by negatively charged nucleophilic reagent

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