pre lab exercise please stimng hai hree 250 mL beakers solution 0Macetic acid, H

Question

pre lab exercise please

stimng hai hree 250 mL beakers solution 0Macetic acid, HC Hyo 00 ml, graduated cylinder id sodium acetate, Nacil 25 mL grad uated cylinder lity clamp balanc ring stand PRE-LAB EXERCISE Use the Henderson-Hasselbalch equation to perform the following calculations, The acid 1.8 x 0 Review your calculations with your instructor before preparing the bumer solutions. Buffet A: Calculate the mass of solid sodium acetate required to mix with 100.0 mL ofo.1 M acetic acid to prepare a pH 4 buffer. Record the mass in your data table. Buffer B: Calculate the mass of solid sodium acelate required to th 100.0 mL of 1.0 M acetic acid to prepare a pH 4 buffer. Record the mass in your data table. PROCEDURE Prepare and Test Buffer Solution A 1. obtain and wear goggles. 2, Use your calculations from the to prepare 100 ml. of Buffer A. Wagh um acetate and dissolve it in 100,0 mL of 0.1 Macetic acid solution. the precise mass of sod

Explanation / Answer

(A)

According to Henderson - Hasselbatch equation of buffer,

pH = pKa + Log[salt]/[acid]

4 = 4.74 + log[salt] / (0.1)

- 0.74 = Log[salt]/(0.1)

[salt] / 0.1 = 0.182

[salt] = 0.0182 M

Moles of salt / 0.100 = 0.0182

Moles of salt = 0.00182 mol

Mass / molar mass = 0.00182

Mass of salt = 0.00182 * 82

Mass of salt or sodium acetate = 0.149 g.

(B)

According to Henderson - Hasselbatch equation of buffer,

pH = pKa + Log[salt]/[acid]

4 = 4.74 + log[salt] / (1.0)

- 0.74 = Log[salt]/(1.0)

[salt] / 1.0= 0.182

[salt] = 0.182 M

Moles of salt / 0.100 = 0.182

Moles of salt = 0.0182 mol

Mass / molar mass = 0.0182

Mass of salt = 0.0182 * 82

Mass of salt or sodium acetate = 1.49 g.

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