A certain city municipal water company contains 0.028 ppm of silver in its water

Question

A certain city municipal water company contains 0.028 ppm of silver in its water. How many liters of water are required to recover 1.00 gram of silver from the water?
Please show all work with the correct answer. Thank you!!! A certain city municipal water company contains 0.028 ppm of silver in its water. How many liters of water are required to recover 1.00 gram of silver from the water?
Please show all work with the correct answer. Thank you!!!
Please show all work with the correct answer. Thank you!!!

Explanation / Answer

Answer:-

silver in water = 0.028 ppm = 0.028 mg/L

= 0.028 x 10-3 g/L

= 2.8 x 10-5 g/L

So,

2.8 x 10-5 g of silver is in = 1 L water

1 g of silver will = 1/ 2.8 x 10-5 L water

= 35714.29 L water

= 3.6 x 104 L water.

so,  3.6 x 104 L water is required to recover 1 g of silver

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