The Slater determinant is a powerful tool for building atomic wavefunctions. How

Question

The Slater determinant is a powerful tool for building atomic wavefunctions. However, it suffers from a major deficiency. Which statement below best qualifies this deficiency?

A) The resulting wavefunction is not guaranteed to be antisymmetrized with respect to electron spin. B) It only correctly predicts the wavefunction for excited states. C) It gives incorrect wavefunctions for excited states when two spin states are near in energy. D) It only works for many-electron atoms with less than ten electrons.

Explanation / Answer

The wavefunction is guaranteed to be antisymmetric. Other functions are automatically rejected.

It predicts wavefunctions for ground as well as excited states correctly.

It works for any number of electrons.

C) It gives incorrect wavefunctions for excited states when two spin states are near in energy.

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.