Sodium plus oxygen gas will produce sodium oxide: 4Na 0 + O 2 0 2Na 2 O Note: Wh
ID: 492199 • Letter: S
Question
Sodium plus oxygen gas will produce sodium oxide: 4Na0 + O20 2Na2O
Note: When water is added to sodium oxide, NaOH is produced: Na2O + H2O 2 NaOH
Based on the 1st reaction, match the following below correctly.
A. Sodium metal
B. oxygen gas
C.sodium ion
D. oxide ion
E. How many electrons got transferred? 4Na0 + O20 2Na2O
F. sodium ion charge
G. oxide ion charge
Choices:
oxidation number is zero - it has not reacted yet.
4
Always +1, it is in Group I, everyone there will always have a +1 charge.
Remember, Group I = +1.
This ion has gained electrons so it has been reduced.
It shall be called the oxidizing agent because it is oxidizing the species that it took the electrons from.
oxidation number is zero, eventhough it is diatomic, it has not combined with anything else.
This ion has lost electrons so it has been oxidized.
It shall be called the reducing agent because it is reducing the species that it gave the electrons to.
G. -2, it is in Group VI.
A. Sodium metal
B. oxygen gas
C.sodium ion
D. oxide ion
E. How many electrons got transferred? 4Na0 + O20 2Na2O
F. sodium ion charge
G. oxide ion charge
Choices:
A.oxidation number is zero - it has not reacted yet.
B.4
C.Always +1, it is in Group I, everyone there will always have a +1 charge.
Remember, Group I = +1.
D.This ion has gained electrons so it has been reduced.
It shall be called the oxidizing agent because it is oxidizing the species that it took the electrons from.
E.oxidation number is zero, eventhough it is diatomic, it has not combined with anything else.
F.This ion has lost electrons so it has been oxidized.
It shall be called the reducing agent because it is reducing the species that it gave the electrons to.
.G. -2, it is in Group VI.
Explanation / Answer
Sodium metal has oxidation number 0
hence A- A
Oxygen gas ( O2) has zero oxidation state even though its diatomic
B-E
Sodium has lost electrons , hence it is oxidised. and acts as reducing agent
C-F
Oxygen has gained electrons to become oxide ion . It acts as oxidising agent
Hence D-D
In the reaction 4 electrons got transferred ( i.e 4Na got oxidised to 4Na+ )
Hence E- B
Sodium ion charge is always +1 since sodium is group I
hence F-C
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