A student obtains 100 mL of a 0.0003627 M solution of AgNO_3 (silver nitrate). H
ID: 492059 • Letter: A
Question
A student obtains 100 mL of a 0.0003627 M solution of AgNO_3 (silver nitrate). He labels this "solution #1". He then pipets 5 mL of Solution #1 into a 50 mL volumetric flask and dilutes to the mark with water. He labels this "Solution #2." He then pipets 10 ml of Solution #1 into a 250 mL volumetric flask and dilutes to the mark with water. This is "Solution #3". Finally, the prepares "Solution #4" by pipetting 16 mL of solution #3 into a 50 mL volumetric flask and dilutes to the mark with water. Draw relational pictures to illustrate the relationship between the original solution and all of the diluted solutions that the student prepared. What is the concentration of silver nitrate in Solution #4?Explanation / Answer
solution 1 is100mL of 0.0003622 M silver nitrae soution.
M of solution 1 = 3.622x10-4 M
2) 5mL of this solution is diluted to50mL .
new molarity of solution2 = 5x3.622x10-4 M/50
= 3.622x10-5 M
3) Then 10mL of solution 1 is diluted to 250mL .
the molarity of solution 3 = 10x3.622x10-4 M /250
= 1.44x10-5M
4) finally 16mL of solution 3 is diluted to 50mL
molarity of solution 4 = 16x 1.44x10-5M/50
= 4.6x10-6 M
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