3/5/2017 11:55 PM G813/100 a mme Remaining: 59 M57s Grar Print Calculator Period

Question

3/5/2017 11:55 PM G813/100 a mme Remaining: 59 M57s Grar Print Calculator Periodic Table Question 3 of 16 Sapling Learning Au a given temperature, the elementary reaction A B in the forward direction is first order in A with a rate constant of 230 x 102 s 1. The reverse reaction is frst order in B and the rate constant is 6.60 x 102 s 1 What is the value of the equilibrium constant for the reaction A B at this temperature? What is the value of the equilibrium constant for the reaction B A at this temperature? O Previous Check Answer 0Next a Exit ut us careers partners privacy policy terms of use contact us l help JBC

Explanation / Answer

1)

equilibrium constant Kc = Kf / Kr

                                      = 2.30 x 10^-2 / 6.60 x 10^-2

                                      = 0.348

2)

equilibrium constant Kc = 1 / 0.348

                                      = 2.87

Related Questions

Navigate

• Browse (All)
• Browse 3
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.