At the very beginning of Step 8 in the Project 8A procedure you will have two la
ID: 491787 • Letter: A
Question
At the very beginning of Step 8 in the Project 8A procedure you will have two layers: an upper (less dense) and a lower (more dense) layer as schematized in the diagram below. On the diagram below write-in the NUMBER of the chemical species that will predominate in each layer at the beginning of Step 8. Just before you add the first 1 mL of 3M HCl in Step 12 in the Project 8A procedure which of the chemical species on the right will predominate in the 50 mL beaker? At the conclusion of Step 12 in the Project 8A procedure which of the chemical species on the right will predominate in the 50 mL beaker?Explanation / Answer
Separation of compounds by liquid-liquid extraction method
Soln. 1. Upper less dense layer is organic and lower more dense layer would be aqueous phase.
The more polar components would dissolve preferentially in aqueous phase and less polar compounds would go in the organic phase.
Compounds in the two layers would be thus,
Top layer : 2, 3, 5
Bottom layer : 1, 4, 6
Soln. 2. Just before adding HCl to the beaker, the predominate species in the beaker present would be, 4 and 5. 4 will be charged and 5 is in neutral form.
Soln. 3 : After complete addition of HCl to the solution in beaker, the chemical species that would predominate in the 50 ml beaker would be the following, 3, 6. 3 in neutral form and 6 is in charged form.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.