The first picture is the info given, and the second is the question. Please expl

Question

The first picture is the info given, and the second is the question. Please explain how you get your answer, I really want to understand. Thank you in advance :) A certain blend of gasoline (a fuel that is a hydrocarbon) requires 14 parts of air to one part gasoline for optimal combustion (14:1 mass:mass ratio). Gasoline weighs about 2.6 kg/gallon (assuming it is nearly all octane) The automobile that is burning this fuel at that l4:1 ratio runs for 50 miles on one gallon of gasoline. Assume complete, clean combustion of this gasoline with oxygen.

Explanation / Answer

Given that;

Gasoline requires 14 parts air to burn by mass

Means 14 kg air:1 kg gasoline

50 miles = 1 kg gasoline

125 miles = 1 kg gasoline /50 miles * 125 miles

= 2.5 kg gasoline

Now required air

14 kg air / 1 kg gasoline = x kg air / 2.5 kg gasoline

X kg of air = 35 kg air

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