If 0.500 mol of acetylene (C_2 H_2) is allowed to completely react with oxygen,

Question

If 0.500 mol of acetylene (C_2 H_2) is allowed to completely react with oxygen, what is the final yield of CO_2 in moles? 2 C_2 H_2(g) + 5)_2 rightarrow 4 CO_2(g) + 2 H_2 O(g) 0.500 mol 1.00 mol 2.00 mol 4.00 mol 0.100 mol How many grams of MgO are produced when 40.0 grams of O_2 react completely with Mg? 2Mg (s) + O_2 (g) rightarrow 2MgO (s) 30.4 g 50.4 g 60.8 g 101 g 201 g How many grams of are required to produce 145 of N_2 in the following reaction? 4 NH_3 (g) + 6 NO(g) rightarrow 5N_2 (g) + 6 H_2 O (l) 186 g 155 g 125 g 129 g 145 g How many grams of water are produced the reaction of of 40.3 g of oxygen according to this equation? 2 H_2 (g) + O_2(g) rightarrow 2 H_2 O (g) 0.630 g 22.7 g 40.3 g 2.00 g 45.3 g

Explanation / Answer

2 C2H2 + 5 O2 = 4 CO2 + 2 H2O

2 mole 5 mole 4 mole 2 mole

2 moles of acetylene gives 4 moles of CO2

1 moles of acetylene gives 2 moles of CO2

0.5 moles of acetylene gives 1 moles of CO2

Answer 27) is (b) 1 mol of CO2

2Mg(s) + O2(g) = 2MgO(s)

2 mole 1 mole 2 mole

Given 40 g of O2

Molar mass of O2 = 32 g

No. of moles of O2 = Mass / molar mass = 40 /32 = 1.25 moles

when 1.25 moles of O2 react completely with Mg it will give 2.5 moles of MgO

Molar mass of MgO = 40.3 g/mol

Mass of MgO = No. of moles * Molar mass = 2.5 mol * 40.3 g/mol = 100.75 g = 101 g

Answer 28) (D) 101 g of MgO

4 NH3 + 6 NO = 5 N2 + 6 H2O

4 mole 6 mole 5 mole 6 mole

Given 145 g of N2 is produced

Molar mass of N2 = 28 g/mol

No. of moles of N2 produced = 145 g / 28 g/mol = 5.1785 moles

Molar mass of NO = 30 g/mol

6 mole of NO is needed for 5 mole of N2 to be produced

No. of moles of NO required = 6 * 5.1785 / 5 = 6.214 moles of NO

Mass of NO required = 6.214 * 30 = 186 g

Answer 29) (A) 186 g of NO

2 H2 + O2 = 2 H2O

2 mole 1mole 2 mole

Given 40.3 g of O2

Molar mass of O2 = 32 g

No. of moles of O2 = Mass / molar mass = 40.3 /32 = 1.259 moles

when 1.25 moles of O2 react completely with Mg it will give 2.518 moles of H2O

Molar mass of H2O = 18 g/mol

Mass of H2O = No. of moles * Molar mass = 2.518 mol * 18 g/mol = 45.34 g = 45.34 g

Answer 29) (D) 45.34 g of H2O

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