Homework questions help is needed Thank you :) Why is reduction of camphor to bo

Question

Homework questions help is needed Thank you :)
Why is reduction of camphor to borneol more selective for one isomer than the other? It's achrial The reducing agent is small One side is more sterically hindered than the other It's just does
If you start with 2.0 mmol camphor, how much methanol do you need to prepare a 1.15 M solution? 1.7ml 5.2 ml 1.7 L 5.2 L
Homework questions help is needed Thank you :)
Why is reduction of camphor to borneol more selective for one isomer than the other? It's achrial The reducing agent is small One side is more sterically hindered than the other It's just does
If you start with 2.0 mmol camphor, how much methanol do you need to prepare a 1.15 M solution? 1.7ml 5.2 ml 1.7 L 5.2 L
Thank you :)
Why is reduction of camphor to borneol more selective for one isomer than the other? It's achrial The reducing agent is small One side is more sterically hindered than the other It's just does
If you start with 2.0 mmol camphor, how much methanol do you need to prepare a 1.15 M solution? 1.7ml 5.2 ml 1.7 L 5.2 L

Explanation / Answer

Reduction of camphor to borneol more selective for one isomer than the other because one side is more sterically hindered than the other.

molarity = number of moles of camphor / volume of solution in L

1.15 = 0.002 mole / volume of solution in L

volume of solution in L = 0.002 / 1.15 = 0.0017 L

1L = 1000 mL so

0.0017 L = 0.0017 L*(1000 mL /1L) = 1.7 mL

Therefore, option A is correct

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