Exercise 17.34 Given the values of r H , r S , and T below, determine S univ. Pa

Question

Exercise 17.34

Given the values of rH, rS, and T below, determine Suniv.

Part A

rH= 83 kJmol1 , rS= 156 JK1mol1 , T= 297 K

Express your answer as an integer.

SubmitMy AnswersGive Up

Part B

rH= 83 kJmol1 , rS= 156 JK1mol1 , T= 820 K

Express your answer as an integer.

JK1mol1

Part C

rH= 83 kJmol1 , rS= 156 JK1mol1 , T= 297 K

Express your answer as an integer.

SubmitMy AnswersGive Up

Part D

rH= 83 kJmol1 , rS= 156 JK1mol1 , T= 405 K

Express your answer as an integer.

JK1mol1

Part E

Predict whether or not the reaction in part A will be spontaneous.

SubmitMy AnswersGive Up

Part F

Predict whether or not the reaction in part B will be spontaneous.

SubmitMy AnswersGive Up

Part G

Predict whether or not the reaction in part C will be spontaneous.

SubmitMy AnswersGive Up

Part H

Predict whether or not the reaction in part D will be spontaneous.

Exercise 17.34

Given the values of rH, rS, and T below, determine Suniv.

Part A

rH= 83 kJmol1 , rS= 156 JK1mol1 , T= 297 K

Express your answer as an integer.

Explanation / Answer

rH= 83 kJmol1 , rS= 156 JK1mol1 , T= 297 K

S sys   = -156J/mole-K

S surround = -H/T

                      = -(-83000)/297   = 279.46J/mole-K

Suniver   = S sys + S surround

               = -156 +279.46 = 123.46J/mole-k

Part B

rH= 83 kJmol1 , rS= 156 JK1mol1 , T= 820 K

S sys   = -156J/mole-K

S surround = -H/T

                      = -(-83000)/820 = 101.2J/mole-K

Suniver   = S sys + S surround

                  = -156+101.2 = -54.8J/mole-K

Part C

rH= 83 kJmol1 , rS= 156 JK1mol1 , T= 297 K

S sys   = -156J/mole-K

S surround = -H/T

                      = (-83000)/297   = -279.46J/mole-K

Suniver   = S sys + S surround

                 = -156-279.46 = -435.46J/mole-K

Part D

rH= 83 kJmol1 , rS= 156 JK1mol1 , T= 405 K

S sys   = -156J/mole-K

S surround = -H/T

                      = -(-83000)/405 = 204.9J/mole-K

Suniver   = S sys + S surround

                 = -156+204.9 = 48.9J/mole-K

part E

Sunive is positive spontaneous

part-F

Sunive is negative nonspontaneous

part-G

Sunive is negative nonspontaneous

part-H

Sunive is positive spontaneous

Related Questions

Navigate

• Browse (All)
• Browse E
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.