Order and rate law of a reaction The overall order of an elementary step directl

Question

Order and rate law of a reaction The overall order of an elementary step directly corresponds to its molecularity. Both steps in this example are second order because they are each bimolecular. Furthermore, the rate law can be determined directly from the number of each type of molecule in an elementary step. For example, the rate law for step 1 is rate NO The exponent "2" is used because the reaction involves two NO2 molecules. The rate law for step 2 is KNO3 CO k NO CO rate because the reaction involves only one molecule of each reactant the exponents are ommitted. Analyzing a new reaction Consider the following elementary steps that make up the mechanism of a certain reaction Part A What is the overall reaction? Express your answer as a chemical equation. Submit Hints My Answers Give Up Review Part

Explanation / Answer

A) overall reaction is:-

2X+2L=M+2Z

B) the species which appears in steps of a reaction but don't appear in overall reaction is called intermediate.

Here Y is intermediate.

C) rate law for step-1 is

R=k[X]^2

D) rate law for step-2 is

r=K[Y][L]^2

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