A deltion mutation, designateed 9, fails to complement mutants 1,3,5,7 and 8. Wi

Question

A deltion mutation, designateed 9, fails to complement mutants 1,3,5,7 and 8. Wild-type recombinants from mutant 9 and mmutations 3,5, and 8; however, no wild-type recombinants from between mutant 9 and mutant 1 and 7. Another deletion mutation 10 fails to complement mutants 1,4,5,6,8, and 9. Mutant 10 forms wild-type recombinants with mutants 1,5, and 6, but not with mutants 4 and 8. Mutant 9 and mutant 10 form wild-type recombinants. Additional gene mapping information identifies mutants 2 and 3 as the flanking genes in this group of genes. Assuming these mutations (2 and 3) are on opposite ends of the gene map, determine the order of these mutations (1-8) in the region of the chromosome.

How many genes are represented by these mutations? Identify the mutants for each complementation group.

In each coinfection above that is identified as a failure to complement (-), scientists see evidence of recombination producing wild-type growth. How do the scientists distinguish between wild-type growth resulting from complementation and wild-type growth that is due to recombination?

Explanation / Answer

Deletion mutations are those that never revert to wild type. It is possible to identify deletion mutations in two different ways. The mutations that don’t recombine with two other mutations that do recombine with each other are also called deletion mutations. For suppose, mutations 1 and 2 recombine with each other, but mutation 3 does not recombine with mutation 1 nor mutation 3, indicating that mutation 3 is a deletion mutation. Thus, mutation 9 is a deletion mutation here.

Co-infection gives the results of complement analysis and helps us place the mutations in two complement groups. We can notice that mutation 6 does not complement any of the mutants, so it must be a deletion mutation. Therefore, the two complementation groups are (1,2,5) and (4,8,9).

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