Need help filing in the bottom chart. Trial 1 and 2 please. Thank you! mixture F
ID: 487057 • Letter: N
Question
Need help filing in the bottom chart. Trial 1 and 2 please. Thank you! mixture F CA Mass of foam cup with ice/water Mass of Styrofoam cup plus ice/water plus unknown of mixture Mass of beaker us unknown Mass of beaker plus aqueous solution of unknown without the ice Mass of the unknown Mass of the aqueous solution of unknown without the ic Mass of the water without the ice Mass of the water without the ice observed freezing point depression (AT) observed molality (m) of solution Experimental moles of unknown used Experimental molar mass of unknown (MM) Average MM of unknown mol Identity of unknown from table 1 Solid Unknown No FPI12s Trial 1 Trial 2 Lowest temperature of ice/water mixture Lowest temperature of mixture of ice/water plus unknown. Mass of beaker Mass of beaker plus aqueous solution of unknown without the ice TNg Mass of the unknown M Mass of the aqueous solution of unknown without the ice Mass of the water without the ice Mass of the water without the ice 0.21 kg 0.11 Observed freezing point depression (AT Observed molality (m) ofsolution Experimental moles of unknown used mol mol Experimental molar mass of unknown (MM) mol mol Average MM of unknown g/mo Identity of unknown (from table 1) (van't Hoff Factor dissociation Mass 4.29 21112 Mug of MLExplanation / Answer
Fill up the table as below:
Serial no.
Trail 1
Trail 2
1
Lowest temperature of ice/water mixture (C)
0.2
0.1
2
Lowest temperature of mixture of ice/water plus unknown (C)
-1.4
-1.1
3
Mass of beaker (g)
50.74
50.74
4
Mass of beaker plus aqueous solution of water without ice (g)
398.74
438.28
5
Mass of the unknown (g)
10.09
49.33
6
Mass of aqueous solution of unknown without the ice (g)
181.02
220.51
7
Mass of water without the ice (g)
121.20
119.32
8
Mass of water without the ice (kg)
0.121
0.119
9
Observed freezing point depression (C) (1-2)
1.6
1.2
10
Observed molality (m) of the solution
0.86
0.64
11
Experimental moles of unknown used (mole) (10*8 as per the relation molality m = moles of solute/kg of solvent)
0.1041
0.076
12
Experimental molar mass of unknown (MM) (g/mol) (Divide 5/11 to get the value)
I have doubt with the entries in serial number 5 above (mass of unknown). Is there really so much variation in mass in the two trials? How did you measure the mass of unknown? Did you weigh it out or calculated it from somewhere? The entries seem grossly incongruent.
13
Average MM of unknown (g/mol)
Please correct the last step.
14
Identity of unknown
Correct the last step.
15
I (Vant Hoff factor)
Correct the last step.
16
% dissociation
Correct the last step.
Serial no.
Trail 1
Trail 2
1
Lowest temperature of ice/water mixture (C)
0.2
0.1
2
Lowest temperature of mixture of ice/water plus unknown (C)
-1.4
-1.1
3
Mass of beaker (g)
50.74
50.74
4
Mass of beaker plus aqueous solution of water without ice (g)
398.74
438.28
5
Mass of the unknown (g)
10.09
49.33
6
Mass of aqueous solution of unknown without the ice (g)
181.02
220.51
7
Mass of water without the ice (g)
121.20
119.32
8
Mass of water without the ice (kg)
0.121
0.119
9
Observed freezing point depression (C) (1-2)
1.6
1.2
10
Observed molality (m) of the solution
0.86
0.64
11
Experimental moles of unknown used (mole) (10*8 as per the relation molality m = moles of solute/kg of solvent)
0.1041
0.076
12
Experimental molar mass of unknown (MM) (g/mol) (Divide 5/11 to get the value)
I have doubt with the entries in serial number 5 above (mass of unknown). Is there really so much variation in mass in the two trials? How did you measure the mass of unknown? Did you weigh it out or calculated it from somewhere? The entries seem grossly incongruent.
13
Average MM of unknown (g/mol)
Please correct the last step.
14
Identity of unknown
Correct the last step.
15
I (Vant Hoff factor)
Correct the last step.
16
% dissociation
Correct the last step.
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.