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Part the correct the 1. Preparation and number of figures proper values the 2. i

ID: 486795 • Letter: P

Question

Part the correct the 1. Preparation and number of figures proper values the 2. is the Standardization significant and in How of a units many moles of KHP of the Hydroxide were solution in each beaker? 3. How many moles of NaoH were titrated? 4. What is the concentration of NaOH added to each beaker? 5. What is the average molari of NaoH? a. Does this average molarity make sense based on your pre-lab calculations and solution preparation? HINT lf it doesn't, there's a calculation error somewhere! 6. What is the absolute deviation for each beaker? 7. What is the average deviation? 8. hat is the relative average deviation (in ppt) obtained? not? S. Has this solution been standardized why

Explanation / Answer

For Trial 1:

M = mol of NaOH/V

mol of KHP = 204.22 g/mol

mol of KHP = (0.406)/204.22 = 0.001988 mol of KHP

note that ratio is 1:1 so

mol of base = 0.001988

M = mol/V = 0.001988/(24.8*0^-3)

M = 0.08016 of NaOH

For Trial 2:

M = mol of NaOH/V

mol of KHP = 204.22 g/mol

mol of KHP = (0.433)/204.22 = 0.002120 mol of KHP

note that ratio is 1:1 so

mol of base = 0.002120

M = mol/V = 0.002120/(37.5*10^-3)

M = 0.05653 of NaOH

For Trial 1:

M = mol of NaOH/V

mol of KHP = 204.22 g/mol

mol of KHP = (0.425)/204.22 = 0.002081 mol of KHP

note that ratio is 1:1 so

mol of base = 0.002081

M = mol/V = 0.002081 /(33.7*0^-3)

M = 0.06175074 of NaOH

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