You have the following buffer recipe and decide to make up some concentrated sol
ID: 486226 • Letter: Y
Question
You have the following buffer recipe and decide to make up some concentrated solutions first that you won't have to weigh out dry ingredients, wait for them to dissolves, and correct the every time you make it. How much dry do you use for each of the following stock solutions? Show your work and include units in your calculations. 150 mM NaCl (formula weight 58.44g) 10 mM Tris pH 8.0 (formula weight 121 g) 0.2% bovine serum albumin Stocks: 3 M NaCl, 100 mL ____ 1 M Tris, pH 8.0, 100 mL ____ 10% bovine serum albumin, 10 mL _____ Next, how much of each stock (listed below) plus water do you use for 500 mL of the buffer recipe above? Choose units so that your answer is measurable-e.g, not 0.05 L or 50,000 uL, but 50 mL. Show your work and include units in your calculations. 3 M NaCl ____ 1 M Tris, pH 8.0 ____ 10% bovine serum albumin ____ distilled water _____ Finish replicating the following strand of DNA (top), as would be done by DNA polymerase, using only the given RNA primer (bottom, make sure it is aligned to its reverse complemet 5' -CGACGTAGCTCGATCACGTAATATACGCATCGACTCCCGATCGA-3' UGCAUUAUAUGCGUA. Draw an origin of replication that is being replicated by DNA polymerase. Label 5' and 3' ends of DNA template. Label RNA primers with 5' and 3' ends. Draw leading strands and lagging strands with arrowheads at the end of the strands indicating the direction of replication. Indicate position of theExplanation / Answer
1)
3 M NaCl =100 mL
3 M x 50 =100 mL x 50
150=5000 mL
0.150 M = 5 mL
150 mmole requires 5 mL
i.e. 17.532 gm in 100 ml solution
therefore
17.532 gm =100 mL (3M)
X= 5mL
X=17.532 x 5 / 0.350 gm.
X=0.8766 gm
2) 1M = 100mL
10 M= 1000 mL
10 mmol= 1 mL
121 gm in 1 Lit = 1M
12.1 gm in 100 mL=1 M
Answer=0.121 gm
3) mol wt of albumine is 66463 D or 66.463 KD
1 D=1.66 x 10-23 gm
66463 D=1.10 x 10-19 gm
0.110 x 10-19 gm in 10 ml i.e 10%
X=0.2 x 0.110 x 10-19 /10
X=2.2 x 10-21 gm
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