The following quantities are placed in a container. 1.9810 24 atoms of hydrogen,

Question

The following quantities are placed in a container.

1.981024 atoms of hydrogen, 1.27 mol of sulfur, and 116.2 g of diatomic oxygen

(a)

What is the total mass in grams for the collection of all three elements?

(b)

What is the total number of moles of atoms for the three elements?

(c)

If the mixture of the three elements formed a compound with molecules that contain two hydrogen atoms, one sulfur atom, and three oxygen atoms, which substance is consumed first?

hydrogensulfur     oxygennone of the above

(d)

How many atoms of each remaining element would remain unreacted in the change described in (c)?

hydrogen

sulfur

oxygen

Explanation / Answer

a)
mol of H atom = total atoms / avogadro's number
= (1.98*10^24)/(6.022*10^23)
= 3.29 mol
mass of H = 3.29 mol * 1 g/mol = 3.29 g

molar mass of S = 32 g/mol
mass of S = number of mol * molar mass
= 1.27 mol * 32 g/mol
= 40.64 g

mass of O = 116.2 g

total mass = 3.29 + 40.64 + 116.2 =160.13 g
Answer: 160.13 g

b)
mol of H = 3.29 mol
mol of S = 1.27 mol

mol of O = mass of O/molar mass of O
= 116.2/16
= 7.26 mol

total moles = 3.29 + 1.27 + 7.26 = 11.82 mol
Answer: 11.82 mol

c)
S is consumed first

d)
atom of H = total H atom - 2*atom of S
= 1.98*10^24 - 2*(1.27*6.022*10^23)
= 4.5*10^23 atom

atom of S = 0

atom of O = (7.26 - 3*1.27)*6.022*10^23
= 2.1*10^24 atom

Answer: 2.1*10^24 atom

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