I cannot figure out what y=mx+b is suppose to be on the excel graph bc it gives

Question

I cannot figure out what y=mx+b is suppose to be on the excel graph bc it gives me 3 diff options (Ln, Temp, atm). (we have to display the chart on the graph, this is what the TABLE should look like in excel, i have listed the steps on the paper)

1/T LnP Temp(k) Press(atm) 0.003922 3.034953 255 20.8 0.003846 3.202746 260 24.6 0.003759 3.356897 266 28.7 0.003676 3.508556 272 33.4 0.003597 3.653252 278 38.6 0.003534 3.793239 283 44.4 0.00346 3.927896 289 50.8 0.003401 4.060443 294 58 0.003333 4.188138 300 65.9 On test 7 erform the following: a) Plot the following dat (using ExcEL) for substance x. Be certain to attach graph to the end of the assignment for complete credit!) b) Determine the heat of vaporization (AHn in JImol for the substance. (sHow WORK!) c) Determine the substance's Normal Boiling Point in oc. (sHow WORK!) Temperature (OF) Vapor Pressure (psi) SS 0.00 306 AH n (P 10.0 24, e 1361 Note 20.0 2 30.0 23, 491 223 40.0 567 AH 83 50.0 slope 652 89 60.0 0,8 747 normal P. latm 30a 80.0 excel imput n corner of e uox mighlig all looxes SCA Hw no Scatt out more trendline Dur display equal ban on mxtb a ppears

Explanation / Answer

dHvap comes from the slope

Recall that:

ln(P2/P1) = -dHvap/R*(1/T2-1/T1)

so...

slope --> m = -dHvap/R

Once you get dHVap

For normal boling poiunt assume P = 1 atm or equivalent units

simply get 1 point of your known data

then, solve for T1

ln(P2/P1) = -dHvap/R*(1/T2-1/T1)

ln(P2/P1) * R / dHvAp + 1/T2 = 1/T1

T1 = [ln(P2/P1) * R / dHvAp + 1/T2 ]^-1

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