Beginning: 6000 µS As H2SO4 is added: 5999-100 µS At equivalence point: 0 µS you
ID: 482428 • Letter: B
Question
Beginning: 6000 µS As H2SO4 is added: 5999-100 µS At equivalence point: 0 µS your conductivity measurements in terms of what is happening at the ionic level for each of the following point in the titration of Ba(oH)2 with Hzso, Specifically, identify what is in solution and why the solution is more or less conducting. a. At the beginning of the titration. before any Haso, is added. b. As the H2So, is added slowly, producing Basofs and H200). c. At the equivalence point (when moles of H2so, added equals the number of moles of Ba(oH2 originally present) After the equivalence point, as excess H2So, is added.Explanation / Answer
a) Beginning of the titration there is only Ba(OH)2. Ba(OH)2 is strong base and will dissociate completely into water as Ba+2 and 2OH- ions. Since, there is the availability of these mobile ions, the conductivity of the solution will increase.
Answer: conductivity of the solution is high.
b)As H2SO4 is added to the solution slowly, Ba(OH)2 reacts with H2SO4 and produces BaSO4, which precipitates out of the solution. BaSO4 is not soluble in water. As a result there will be fewer mobile ions left to conduct electricity. So, the conductivity of the solution will go down.
Answer: Conductivity decreases by the addition of H2SO4.
c) H2SO4 + Ba(OH)2 ----> BaSO4 + 2H2O
In this reaction, one mole of H2SO4 will neutralize one mole of Ba(OH)2. So, adding equal number of moles of H2SO4 will completely neutralize the original Ba(OH)2 and the resulting BaSO4 will precipitate out. So, there will no mobile ions left in the solution at equivance point. Therefore, the conductivity will be zero.
Asswer: No conductivity at equivance point (almost zero).
d) After the equivalence point, there will be excess H2SO4 provide to the solutiion. So H2SO4 dissociates into 2H+ and SO4-2 ions. Since, there is availability of mobile ions, to the solution, the conductivity will again rise with the addition of excess H2SO4.
Answer: Conductivity rise again excess addtion of H2SO4 to the solution after equivalence point.
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