As part of a kinetics experiment, a student plots three graphs: [[C_4H_6]. M vs.
ID: 480828 • Letter: A
Question
As part of a kinetics experiment, a student plots three graphs: [[C_4H_6]. M vs. Time, s In [C_4H_6] vs. Time, s 1/[C_4H_6]. 1/M vs. Time's and determines that the pot of 1/[C_4H_6], 1/M vs. Time, s has the greatest correlation coefficient (has data points that correspond the most to a linear response). The equation of this pot is y = 0.0614x + 100.0 What order is this reaction with respect to the the butadiene molecule? What is the k-value for this reaction? And the units What is the rate law of this reaction with respect to the butadiene molecule? What is the rate of a reaction (related to this experiment) given a butadiene concentration of 0.00350 M?Explanation / Answer
a)
For 1/[C4H6] vs time, this must be SECOND ORDER
since
dCa^2 / d^2t = k*Rate; will give a striaght line vs. time when solving for [Ca]
b)
in this specific case
slope = m = k
so
k = 0.0614 1/(Ms)
c)
rate law, must be second order so:
Rate = -k*[C4H6]^2
d)
rate of reaction when... [C] = 0.0035
Substitute:
Rate = -k*[C4H6]^2
Rate = -0.0614*(0.0035^2) = -7.52*10^-7 M/s
negative, since this is REACTION and not production
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