Optional extra credit: You are working in an industrial lab and are charged with

Question

Optional extra credit: You are working in an industrial lab and are charged with waste reclamation. The waste that you are working with contains silver chloride and lead (II) chloride. Both compounds are insoluble in cold water: however, lead (In chloride is soluble in hot water. Your lab is equipped with beakers, stirring rods, filter paper, a hot plate, a suction filtration apparatus, deionized water, and an oven. Write the chemical formulas for silver chloride and lead (II) chloride. Propose a procedure for separating these two components. After completing the separation, you find out that the percent recovered for one of the components is low. Based on your purposed procedure, briefly explain which component has the low percent recovery and why.

Explanation / Answer

a) The formula of Silver chloride is AgCl and lead(II) chloride is PbCl2

b) If we add hot water to the mixture solution and followed by filtration can separate the two compounds. In this residue is AgCl and PbCl2 will be a filtrate. PbCl2 separated from the solution by using recrystallization process.

c) PbCl2 recovery is less because of the errors of the recrystalization process.

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