please answer the following : a) Calculate the number of molecules in 5.46 mg of
ID: 480139 • Letter: P
Question
please answer the following :
a) Calculate the number of molecules in 5.46 mg of laughing gas (N2O).
b) Calculate the mass (in grams) of 9.79 x 1013 molecules of riboflavin, C17H20N4O6.
c) The fermentation of sugar to produce ethyl alcohol occurs by the following reaction:
What mass of ethyl alcohol can be made from 0.597 kg of sugar?
d) A fast-food restaurant makes double cheeseburgers using one hamburger roll, two quarter-pound patties of beef, one slice of cheese, a fourth of a tomato, and 15 g of shredded lettuce. At the start of the day, the restaurant manager has 18 dozen rolls, 38 lb of beef patties, 4 packages of sliced cheese containing 65 slices each, 49 tomatoes, and 3 kg of lettuce. Which ingredient will run out first, and how many cheeseburgers can be made?
e) Determine the molecular formula and calculate the molar mass (in g/mol) of arginine, the essential amino acid. The formula should be entered as CwHxNyOz, followed by other element if any.
yeastExplanation / Answer
a)
mass of N2O = 5.46 mg = 5.46 x 10^-3 g
moalr mass of N2O = 44 g/mol
moles of N2O = 5.46 x 10^-3 / 44 = 1.24 x 10^-4 mol
for 1 mol of N2O have -------- 6.023 x 10^23 molecules
1.24 x 10^-4 mol -------------- ?? molecules
number of N2O molecules = 1.24 x 10^-4 x 6.023 x 10^23
= 7.47 x 10^19 molecules
b) Calculate the mass (in grams) of 9.79 x 1013 molecules of riboflavin, C17H20N4O6.
number of molecules = 9.79 x 1013
molar mass of riboflavin = 376 g/mol
moles of riboflavin = 9.79 x 1013 / 6.023 x 10^23
= 1.625 x 10^-10 mol
moles = mass / molar mass
1.625 x 10^-10 = mass / 376
mass of riboflavin = 6.11 x 10^-8 g
c)
C6H12O6 (s) -----------> 2C2H5OH(l) + 2CO2 (g)
180 g 92 g
597 g ??
180 g sugar ---------- 92 g ethyl alcohol
597 g sugar ------------ ??
mass of ethyl alcohol = 597 x 92 / 180
= 305 g
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.