For acid neutralization problem the volumetric flowrate of the HCL solution comi

Question

For acid neutralization problem the volumetric flowrate of the HCL solution coming from our manufacturing process is 11600 L/hr, and the average concentration of HCl in that stream is 0.014 M or 0.014 gmol/L. Based on this information calculate

a. How many gmol of HCl are in 88m3 of the solution?

b. How many gmol of HCl are flowing from the process per minute (i.e. what is the molar flow rate) when the volumetric flow rate of the solution is 11600 L/hr?

c. What is the mass fraction of HCl in the solution?

I need help with Part C!

Please include conversions and steps.

Explanation / Answer

0.014 M = 0.014 mol/L

Now, 1 mol = 36.5 gm

So, 0.014 mol = 0.014 mol * 36.5 g/mol = 0.511 g

Density of water = 1gm/mL

Mass of 1L of solution = 1000mL * 1gm/mL = 1000gm

Mass fraction = mass of HCl/mass of water + HCl

                    = 0.511g/1000g + 0.511g = 0.0005

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