Used the above formula to answer the question and made sure to correctly notate

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Used the above formula to answer the question and made sure to correctly notate the ( - ) sign with the answers. I worked the problem before an expert answer was posted and will be leaving the post in order to help current or future students.

A loss of 0.6 mg of Zn occurs in the course of an analysis for that element Calculate the percent relative error due to this loss if the mass of Zn in the sample is a. 60 mg. Percent relative error = % b. 130 mg. Percent relative error = % c. 350 me. Percent relative error = % d. 500 mg. Percent relative error = % A loss of 0.6 mg of Zn occurs in the course of an analysis for that clement. Calculate the percent relative error due to this loss if the mass of Zn in the sample is a. 60 mg. Percent relative error = 0.99 % b. 130 mg. Percent relative error = -0.46 % c. 350 mg. Percent relative error = -0.17 % d. 500 me. Percent relative error = -0.12 % Use the following formula to calculate the percent relative error. %relative error = |experimental value (x_i)- true value(x_i)/true value (x_i)| times 100%

Explanation / Answer

a)
experimental value = 60 mg
true value = 60 mg + 0.6 mg = 60.6 mg

%relative error = (experimental value - true value)*100 / true value
= (60 - 60.6)*100/60.6
= -0.6*100/60.6
= -0.99 %

b)
experimental value = 130 mg
true value = 130 mg + 0.6 mg = 130.6 mg

%relative error = (experimental value - true value)*100 / true value
= (130 - 130.6)*100/130.6
= -0.6*100/130.6
= -0.46 %

c)
experimental value = 350 mg
true value = 350 mg + 0.6 mg = 350.6 mg

%relative error = (experimental value - true value)*100 / true value
= (350 - 350.6)*100/350.6
= -0.6*100/350.6
= -0.17 %

d)
experimental value = 500 mg
true value = 500 mg + 0.6 mg = 500.6 mg

%relative error = (experimental value - true value)*100 / true value
= (500 - 500.6)*100/500.6
= -0.6*100/500.6
= -0.12 %

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