Use the References to access important values if needed for this question. a. en

Question

Use the References to access important values if needed for this question. a. energy increments in the OWL Table Reference (see References button, strain Energy Increments) to b. calculate the energy difference between the two chair conformations of the compound below. Specify substituent positions (axial or equatorial in the more stable chair. c. Estimate the percent of the more stable chair at equilibrium at 25°C. (To determine the percent of the more stable chair at first calculate this value to find the percentage.) Keq, and then use CH NEC Answers: a. The energy difference is mol b. In the more stable chair: o The methyl group is in the E position o The cyano group is in the position. c. At 25c the equilibrium percent of the more stable chair conformation is approximately Submit Answer Retry Entire Group 9 more group attempts remaining

Explanation / Answer

For the first molecule

a. Energy difference = 7.82 kJ/mol

b. In the more stable chair conformation

CH3 is in equatorial posiiton

CN is in equatorial position

c. At 25 oC the percentage of more stable chair conformation is apporximately = 96%

For the second molecules

a. the energy difference = 1.90 kJ/mol

b. In the most stable chair conformation,

CH3 is in axial position

isopropyl group is in equatorial posiiton

c. At 25 oC the percentage of more stable chair conformation is apporximately = 68.5%

Third molecule

a. the energy difference = 9.70 kJ/mol

b. In the most stable chair conformation,

CH3 is in equatorial position

OCH3 group is in equatorial posiiton

c. At 25 oC the percentage of more stable chair conformation is apporximately = 98%

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