Find concentration of each substance in each trial use the equation M1V1=M2V2, w
ID: 479867 • Letter: F
Question
Find concentration of each substance in each trial use the equation M1V1=M2V2, where M1 is the concentration of the original solution, V1 is how much of it you used to make the solutions, V2 is the total volume of the mixed solution (volumes of A+B).
Trial 4 Solution A Trial 1 ria 2 Trial 3 Potassium lodate 5 mL 10 mL 2.5 mL 5 mL Solution, 0.20 M Distilled Water 15 mL 10 mL 17.5 mL 15 mL Sulfuric Acid 0 mL 0 mL 0 mL 0 mL Solution, 0.1 M Solution B Trial 1 Trial 2 Trial 3 Trial 4 1 mL 2 mL Sodium 1 mL Metabisulfite Solution, 0.20 M 4 4 mL 3 mL Distilled Water 4 mL 4 mL Starch Solution mL m Trial 5 15 mL 0 mL Trial 5 0.5 mL 4.5 mL m Trial 6 14 mL 1 mL Trial 6 1 mL 4 mL 3 mLExplanation / Answer
The calculations are extremely simple and straight-forward.
I am showing the calculations for a couple of cases, and you can follow up for the rest very easily.
Solution A Trial 1:
Total volume = 5 + 15 = 20 mL
Final conc. of Potassium Iodate solution: (Using relation M1V1 = M2V2)
0.2 * 5 = M2 * 20
So, M2 = 0.05 M
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Solution A Trial 6:
Total volume = 5 + 14 + 1 = 20 mL
Final conc. of Potassium Iodate solution: (Using relation M1V1 = M2V2)
0.2 * 5 = M2 * 20
So, M2 = 0.05 M
Final conc. of Sulfuric acid solution: (Using relation M1V1 = M2V2)
0.1 * 1 = M2 * 20
So, M2 = 0.005 M
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Solution B Trial 1:
Total volume = 1 + 4 + 3 = 8 mL
Final conc. of Sodium metabisulfite solution: (Using relation M1V1 = M2V2)
0.2 * 1 = M2 * 8
So, M2 = 0.025 M
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Solution B Trial 5:
Total volume = 0.5 + 4.5 + 3 = 8 mL
Final conc. of Sodium metabisulfite solution: (Using relation M1V1 = M2V2)
0.2 * 0.5 = M2 * 8
So, M2 = 0.0125 M
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