Map Sapling Learning Calculate the concentration of IO n a 6.70 mM Pb(NO3)2 solu

Question

Map Sapling Learning Calculate the concentration of IO n a 6.70 mM Pb(NO3)2 solution saturated with Pb(IO3)2. The Ksp of Pb(IO3)2 is 2.5 x 10-3 Assume that Pb(IO3)2 is a negligible source of Pb compared to Pb(NO3)2 Number IO 6.4 x 10 M A different solution contains dissolved Nalo3. What is the concentration of Nalo3 if adding excess Pb(IO32(s) produces [Pb21 7.00 x106 M? Incorrect. Create an equilibrium table for the dissolution of Number Pb(IO32 in a solution of NaIO Let the concentration of NalO NaIO 1.09 M in solution be y, so that the initial concentration of IO3 is y Pb2+(aq) 21o (aq) Initial (M) Change +2x +X Equilibrium y+ 2x The equilibrium constant expression is You know that 7.00 x 106 M. Substitute in the expressions from the Pb spr equilibrium table into the equation on the left and solve for y. AO Previous Give Up & View Solution Try Again Next Ext

Explanation / Answer

Ksp = [Pb+2][IO3-]^2

in equilibrium:

[PB+2] = x

[IO-3] = y + 2x; where y is the "the most of IO3- from the salt, NaIO3"

so

Ksp = [Pb+2][IO3-]^2

turns to

2.5*10^-13 = x*(y+2x)^2

we know that x = 7*10^-6

so

2.5*10^-13 = (7*10^-6)*(y+2*(7*10^-6))^2

solve for y

y + 2*(7*10^-6) = sqrt((2.5*10^-13 )/(7*10^-6))

y = 0.00018898223-2*(7*10^-6)

y = 0.000174982 M

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