1. When 14.05 mL of Hal of unknown concentration (but less than that of the base

Question

1.

When 14.05 mL of Hal of unknown concentration (but less than that of the base)?

Are reacted with 15mL of 3.005 M NaOH, 1.86 kj of heat are released. What is the molarity of the HCl solution?

When 14.05 mL of Hal of unknown concentration (but less than that of the base)?are reacted with 15 mL of 3.005 M NaOH, 1.86 kJ of heat are released. What is the molarity of the HCl solution? 26.35g of a substance, initially at 99.95 degree C, was poured into 9.88 g of water in a calorimeter. The initial temperature of the water and the calorimeter was 21.55 degree C. The calorimeter has a heat capacity of 7.68 J/K. The temperature after mixing T_f, was determined to be 37.33 degree C. Calculate the specific heat capacity of the substance

Explanation / Answer

1. We know that

When 1 equivalent of a strong acid is neutralised with 1 equivalent of a strong base heat released =-57.1 KJ

So -57.1 KJ heat released by reaction of 1 equivalent

Hence 1.86 KJ heat would be released by (1.86÷57.1) equivalent=0.0325 equivalent

So equivalent of acid=(14.05×M×1)/1000=0.0325

Molarity=M=2.3 molar

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