Sapling Learning You need to prepare an acetate buffer of pH 5.55 a 0.738 M acet

Question

Sapling Learning You need to prepare an acetate buffer of pH 5.55 a 0.738 M acetic acid solution and a 3.00 M KOH solution. If you have 625 mL of the acetic acid solution, how many milliliters of the KoH solution do you need to add to make a bufer of pH 5.55? The pKa of acetic acid is 4.76. Number mL There is additional feedback available! View this feedback by clicking on the bottom divider bar. Click on the divider bar again to hide the additional feedback. Incorrect. Close Explanation O Previous Give Up & View Solution a Try Again e Next d Exit

Explanation / Answer

no of moles of CH3COOH = molarity * volume in L

                                           = 0.738*0.625 = 0.46125moles

PH = PKa + log[CH3COOK]/[CH3COOH]

5.55 = 4.76 + logx/x-0.46125

logx/x-0.46125 = 5.55-4.76

logx/x-461.25 = 0.79

x/x-0.46125     = 100.79

x/x-0.46125    = 6.16

x                   = 6.16*(x-0.46125)

x                 = 0.55

no of moles of KOH = molarity * volume in L

0.55                           = 3*volume in L

volume in L               = 0.55/3 = 0.183L

volume of KOH      = 183ml

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