ry Bookmarks People Window Help m/ibiscmslmodlibis/view.php?id 3225317 1/30/2017

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ry Bookmarks People Window Help m/ibiscmslmodlibis/view.php?id 3225317 1/30/2017 11:55 PM 86/0 Gradebook Print Calculator Periodic Table Question 10 of 15 Sapling Learning Consider this reaction data: you were going to graphically determine the activation energy of this reaction, what points would you plot? products Number T (K) (s point 1: To avoid rounding 325 0.372 three 0.793 figures in all values. point 2: Determine the rise, run, and slope of the line formed by these points. rise What is the activation energy of this reaction? Number J/ mo n Previous Gave up s view solution checks Answer oNed JExt about us careers partners privacy policy terms of use contact us help

Explanation / Answer

The plot will be ln(k) Versus (1/T) [Arrhenius equation]
so, point 1 will be [ 1/325 , ln(0.372) ] = [3.0769*10-3, -0.9888]
point 2 will be, [ 1.9047*10-3, -0.2319]
Rise = -0.2319-(-0.9888) = 0.7569
Run = -1.1722*10-3
slope = rise / run = 0.7569 / (-1.1722*10-3) = -645.7089
-Ea / R = -645.7089
Ea = 8.314 * 645.7089 = 5368.4239 J/mol

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