Provided with the molar mass of a compund, and percent composition, determine th

Question

Provided with the molar mass of a compund, and percent composition, determine the empirical formula, empirical mass, molecular formula, and compound name.
Percent composition: Carbon:43.58 Hydrogen : 3.35 Nitrogen: 8.47 Oxygen: 24.19 Chlorine: 10.72 Sulfur: 9.69
Molar mass: 330.75
Provided with the molar mass of a compund, and percent composition, determine the empirical formula, empirical mass, molecular formula, and compound name.
Percent composition: Carbon:43.58 Hydrogen : 3.35 Nitrogen: 8.47 Oxygen: 24.19 Chlorine: 10.72 Sulfur: 9.69
Molar mass: 330.75

Percent composition: Carbon:43.58 Hydrogen : 3.35 Nitrogen: 8.47 Oxygen: 24.19 Chlorine: 10.72 Sulfur: 9.69
Molar mass: 330.75

Explanation / Answer

Step 1 write the elements with their % composition as subscript

C43.58H3.35N8.47O24.19Cl10.72S9.69

Step 2 devide % composition with corresponding atomic masses of elements

C43.58/12H3.35/1N8.47/14O24.19/16Cl10.72/35.5S9.69/32

C3.63H3.35N0.605O1.51Cl0.302S0.302

Step 3 these numbers with the least number among them here it is 0.302

C3.63/0.302H3.35/0.302N0.605/0.302O1.51/0.302Cl0.302/0.302S0.302/0.302

C12H11.09N2O5Cl1S1

Step4 approximate to the closest whole number

C12H11N2O5Cl1S1

this is the empirical formula

now the empirical mass =(12x12+1x11+2x14+5x16+1x35.5+1x32)=330.5

now molecular formula =empirical formula x( molecular mass/empirical formulamass)

=C12H11N2O5Cl1S1 X(330.75/330.5)

=C12H11N2O5Cl1S1

name of the compound is furosemide

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