Question 14 of 15 Map A Sapling Learning The known concentration of glucose in a
ID: 476875 • Letter: Q
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Question 14 of 15 Map A Sapling Learning The known concentration of glucose in a blood sample is 102.0 mg/dL. During testing of a new at home lucose monitor, the device gives the following determinations of glucose in the blood sample: 107.1, 107.6, 2.7, 93.2, and 96.5 mg/dL, Calculate the absolute error and relative error for each measurement made by the glucose monitor. a) 107.1 mg/dL Number absolute error Number mg/dL relative error b) 107.6 mg/dL Number Number mg/dL relative error absolute error c) 102.7 mg/dL Number Number mg/dL relative error absolute error d) 93.2 mg/dL Number Numn her. Previous 8 Give Up & View Solution Check Answer Next D Ext HintExplanation / Answer
Absolute Error: The absolute error E in a measurement is expressed as
E = xi - xt where xi = measured value and xt = true ( accepted) value
Relative error: The relative error Er in a measurement is expressed as
Er = ( xi - xt )/xt
Relative error is generally expressed as percent
Er = ( xi - xt )/xt X 100
a) 107.1 mg/dl
The absolute error E = xi - xt = 107.1 - 102.0 = 5.1 mg/dl
relative error Er = (107.1 - 102.0)/102.0 X 100 = 5 %
b) 107.6 mg/dl
The absolute error E = xi - xt = 107.6 - 102.0 = 5.6 mg/dl
relative error Er = (107.6 - 102.0)/102.0 X 100 = 5.49%
c) 102.7 mg/dl
The absolute error E = xi - xt = 102.7 - 102.0 = 0.7 mg/dl
relative error Er = (102.7 - 102.0)/102.0 X 100 = 0.68 %
d) 93.2 mg/dl
The absolute error E = xi - xt = 93.2 - 102.0 = -8.8 mg/dl
relative error Er = (93.2 - 102.0)/102.0 X 100 = -8.62 %
e) 96.5 mg/dl
The absolute error E = xi - xt = 96.5 - 102.0 = -5.5 mg/dl
relative error Er = (96.5 - 102.0)/102.0 X 100 = -5.39 %
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