Please annswer Chlorine is produced by the reaction 4HCl(g) + O2(g) = 2H2O(g) +2

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Chlorine is produced by the reaction 4HCl(g) + O2(g) = 2H2O(g) +2Cl2(g) The feed stream to the reactor consists of 60% HCl, 36 mol% O2 and 4 mole % N2, and it enters the reactor at 550oC. If the conversion of HCl is 75% and if the process is isothermal, how much heat must be transferred from the reactor per mole of the entering gas mixture?

1. Chlorine is produced by the reaction The feed stream to the reactor consists of 60% HCL, 36 mol% O: and 4 mole N2, and it enters the reactor at 550PC If the conversion of HCl is 75% and if the process is isothermal, how much heat must be transferred from the reactor per mole of the entering gas mixture? Hint: Take a basis of 1 mole gas entering reactor, containing 0.6 M HCl, 0.36 M O2 and 0.00 MN2. Therefore the amount of HCIreacted (r) is equal to 0.6x0.75-0.45. Using AHass as the reference, we can calculate AHszs using equation 823 AH298 MDCPH-R-CT-1298) where T-298.15 K r Answer: Q -13,229 J

Explanation / Answer

First find H298.

So from literature

H298,Cl2 =0

H298,O2 =0

H298,H2O =-241818 J/mol

H298,HCl =-92307 J/mol

So H298 = Hproduct -Hreactant = 2*(-241818)-4*(-92307) =-1.144*105 J/mol

T0 =298 K

T = 823 K

Now from literature take constants for finding MDCPH (Mean heat capacity)

H2O:

A=3.470,B=1.45*10-3 ,C=0(10-7=0),D=0.121*105

Cl2

A=4.442 ,B=0.089*10-3,C=0,D=-0.344*105

HCl

A=3.156,B=0.623*10-3,C=0,D=0.151*105

O2

A=3.639,B=0.506*10-3,C=0,D=-0.227*105

A= niAi

where n= stochiometry coefficient

nHCl= -4

nO2=-1

nH2O=2

nCl2=2

A= niAi = 2*3.470+2*4.442-1*3.639-4*3.156=-0.439

Same way

B= niBi =8*10-5

C =0

D =-8.23*104

= T/T0 = 823/298 =2.7617

R=8.314 J/mol K

Put all value in this equation

MDCPH =A+(B/2)*T0*(+1)+(C/3)T02(2++1)+D/(.T02)=-0.8194

Now

H823 = H298+MDCPH*R*(T-298)

Put all values in this equation:

H823 =-1.144*105- 0.8194*8.314*(823-298)=-117592 J/mol

Heat transfer per mol enering the reactor

Q= H823*0.45/4=-13229 J

  

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