where possible classify these systems as reactant favored or product favored at

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where possible classify these systems as reactant favored or product favored at 298K. If the direction cannot be determined from the information given, classify the reaction as "insufficient information t View History Bookmarks People Window Help Calculate The Standard Entropy Delta n X O www.saplinglearning.com/ibiscms/mod/ibis/view.php?id-3204168 Print calculator MPeriodic Table Mapab Sapling Learning Where possible, classify these systems as reactant-favored or product-favored at 298 K. lfthe direction cannot be determined from the information given, classify the reaction as "Insufficient information' Reactant-favored Product-favored Insufficient information 2A(g) B (g) 4C(g) 2A(g) B(s) AH +322 kJ AH 193 kJ A(s) 2B(g) C(g) 2A (g) 3B(g) 4C(g) AH +271 kJ AH --95 kJ There is additional feedback View this feedback bottom divider bar bar again to hide the addiional teedback O Previous a Try Again o Next HE 415 Unit 1 Hando....pdf LC 1415 Unit 1 Hando....pdf Wk oz. Dear 2006 Int ....pdf Show All MacBook Pr

Explanation / Answer

i) 2A(g)+C(g)=4C(g), H = +322 KJ

Now, since delta H is +ve, that means the reaction is Endothermic.

Also, entropy of system is increasing, S is +ve.

This is an endothermic reaction with a positive entropy change. Ssyst > 0, but Ssurr < 0, so more information is needed to predict how this reaction will go. Since raising the temperature makes Ssurr smaller, this sort of reaction will be product-favoured at high temperatures and reactant-favoured at low temperatures.

ii) A(s)+2B(g) = C(g) , H= +271 KJ

The above reaction is also endothermic.

And, S is –ve.

This is an endothermic reaction with a negative entropy change. Ssurr < 0, so Suniv < 0 and the reaction is reactant-favoured at all temperatures.

iii) 2A(g)+B(s) = 3C(g)

For the third reaction, H <0 and S >0.

This is an exothermic reaction with a positive entropy change. Ssurr > 0, so Suniv > 0 and the reaction is product-favoured at all temperatures.

iv) 2A(g)+3B(g) = 4C(g)

H<0, and S<0.

This is an exothermic reaction with a negative entropy change. Ssyst < 0, but Ssurr > 0, so more information is needed to decide. Since raising the temperature makes Ssurr smaller, this sort of reaction will be reactant-favoured at high temperatures and product-favoured at low temperatures

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