Propose a reasonable explanation for why the following complex does not readily

Question

Propose a reasonable explanation for why the following complex does not readily undergo beta-hydride elimination from its ethyl group. Explain why CpV(CO)_3(H_2) is a non-classical dihydrogen complex, but CpTa(CO)_3(H)_2 is a dihydride (contains two separate H ligands). Below Is an example of an apparent alkyl-carbine insertion process. In the first step, a hydride ton Is extracted to form intermediate A, which is a cationic ruthenium carbine complex. A rearranges to form the cationic intermediate B, which is thought to undergo rapid beta-hydride elimination to afford the ethylene complex, c Use the reactant(s) and the reaction types to predict the products (A - C) formed in the process below Upload Images of your answers.

Explanation / Answer

7) The complex does not undergo beta elimination from the alkyl group since the complex already having an 18-electron configuration, -hydride elimination is not possible, also the geometry & orientation of the complex also prevents it from undergoing beta elimination.

8) UV photolysis of [cpM(CO)4](cp =5-C5H5; M = V, Nb and Ta) and H2has been studied by IR spectroscopy both in n-heptane solution at 25 °C and in liquid Xenon solution at –110 to –45 °C; for V, the reaction leads to formation of the non-classical complex [cpV(CO)3(2-H2)] while, for Ta, the dihydride [cpTa(CO)3H2] is formed; for Nb, there is a temperature dependent equilibrium between the classical [cpNb(CO)3H2] and non-classical [cpNb(CO)3(2-H2)] compounds, which presents an unusual opportunity to study the formation of these species using nanosecond Time-resolved IR spectroscopy (TRIR).

Dihyrogen give stable adducts with group 6-9 metal complexes whereas unstable complex with group 10,11 & 5 elements.

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