Please see images for question. Also attached is the recorded data from the expe

Question

Please see images for question. Also attached is the recorded data from the experiment, which may be necessary to answer the question.

Other information: Upon graphing each column (time vs absorbance, time vs ln absorbance, time vs 1/absorbance), the graph of time vs ln absorbance indicates a first order reaction, since it was the only linear graph

11 Analyze the data graphically to decide if the reaction is zero, first, or second order with respect to crystal violet. graph is the reaction is order, First order: To see if the reaction is first order, it is necessary to plot of the natural logarithm (In A) of absorbance vs. time. Ifthis plot is linear, the reaction is first order. Second Order: To see ifthe reaction is second order, plot a graph of the reciprocal of absorbance vs. time. Ifthis plot is linear, the reaction is second order. Time (Minutes) A 1/A In A 3.0 4.0 2,793 5S8 5.0 3, ISB 6.0 7.0 I 40S 4.2,29 asl 8.0 09 9.0 -1.242 175 10.0 I. Go4 49 11.0 a 040 130 12.0 12 2.189 8.9 29 13.0 2.243 0.419 14.0 12.048 15.0 16.0 0.813 17.0 OS 2. a. 18.0 04 S 22.222 19.0 20.0 032. 3.442 31.2 S

Explanation / Answer

According to the information given, this is a first order reaction which means that rate of the reaction depends only on the concentration of crystal violet and not on the concentration of OH-.

Rate = k[CV+]

where k = rate constant which can be obtained from the slope of the linear graph and [CV+] is the concentration of crystal violet.

Had it been a second order reaction the mathematical expression for rate is as follows.

rate = k[CV+][OH-]

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