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A process for manufacturing acetylene involves the dehydrogenation of ethane ove

ID: 474810 • Letter: A

Question

A process for manufacturing acetylene involves the dehydrogenation of ethane over a newly discovered catalyst. The process will operate at 1 bar and a yet unspecified temperature. The only reaction is thought to occur entirely in the gas phase: . The following thermochemical data is available:

Component

Go298 (kJ/mole)

Ho298 (kJ/mole)

Ethane

-32.9

-84.7

Acetylene

209.3

226.9

               Please answer the following:

What is the standard Gibbs free energy change at 25oC for this reaction?

What is the standard enthalpy change of reaction at 25oC?

What is the equilibrium constant for this reaction at 25oC?

Assuming the standard enthalpy change is independent of temperature what is the equilibrium constant for this reaction at 827oC?

If we supply pure ethane at 827oC to the reactor at 1 bar, and if equilibrium is obtained, what is the composition of the final product mixture. Assume the reactor operates isothermally at these conditions.

Component

Go298 (kJ/mole)

Ho298 (kJ/mole)

Ethane

-32.9

-84.7

Acetylene

209.3

226.9

Explanation / Answer

C2H6 ------------------------>C2H2 + 2 H2

1)

Gibbs free energy change = Go products - Go reactants

= (209.3 + 2 x 0 ) - (-32.9)

   = 242.2 kJ / mol

standard enthalpy change = Ho products - Ho reactants

= (226.9 + 2 x 0 ) - (-84.7)

   = 311.6 kJ / mol

3) What is the equilibrium constant for this reaction at 25oC?

Go = - RT ln Keq

242.2 = -8.314 x 10^-3 x 298 x ln Keq

ln Keq = -97.76

Keq = 3.49 x 10^-43

equilibrium constant = 3.49 x 10^-43

4) Assuming the standard enthalpy change is independent of temperature what is the equilibrium constant for this reaction at 827oC?

T = 827 + 273 = 1100 K

Go = - RT ln Keq

242.2 = -8.314 x 10^-3 x 1100 x ln Keq

ln Keq = -26.48

Keq = 3.16 x 10^-12

equilibrium constant = 3.16 x 10^-12

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