The heat energy associated with a change in in temperature that does not involve
ID: 474405 • Letter: T
Question
Explanation / Answer
-18oC --------------------> 0oC ------------------> 25oC
(1) (2) (3)
there are 3 steps involved in this process
(1) ice from -18 to 0oC
q1 = m Cp dT = 76 x 2.09 x (0 +18) = 2859,12 J
(2) at fusion:
q2 = m delta H = 76 x 334 = 25384 J
(3) from 0 to 25 oC
q3 = m Cp dT = 76 x 4.18 x 25 = 7942 J
total heat q = q1 + q2 +q3
q = 36185.12 J
q = 3.62 x 10^4 kJ
heat = 3.62 x 10^4 kJ
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