1) CH 3 SH reacts with CO according to the following unbalanced chemical equatio

Question

1) CH3SH reacts with CO according to the following unbalanced chemical equation:

CH3SH + CO CH3CO(SCH3) + H2S

Calculate the mass in grams of the excess reagent remaining after the complete reaction of 6.32 g of CH3SH with 4.73 g of CO.

2) Determine the pH (to two decimal places) of the following solutions. A table of pKa values can be found here. If the 5% approximation is valid, use the assumption to compute pH.

a) 1.44×10-3 M pyridinium ion

b) 4.86×10-3 M sodium acetylsalicylate

c) 2.64×10-2 M phenylamine (aniline)

Explanation / Answer

CH3SH reacts with CO according to the following unbalanced chemical equation:

2 CH3SH + CO CH3CO(SCH3) + H2S

where

moles of CH3SH = 6.32 g / 48.103 g/mol = 0.131 mol

moles of CO = 4.73 g / 28.01 g/mol = 0.169 mol

as we can see that 2 mol of CH3SH reacts with 1 mol of CO.

therefore

CH3SH is the limiting reageent and CO is the excess reagent.

remainig moles of CO = 0.169 mol - ( 0.131 mol / 2 ) = 0.169 - 0.066 = 0.103 mol

and

mass of CO = 0.103 mol x 28.01 g/mol = 2.89 grams

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