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The LP problem whose output follows determines how many necklaces, bracelets, ri

ID: 469905 • Letter: T

Question

The LP problem whose output follows determines how many necklaces, bracelets, rings, and earrings a jewelry store should stock. The objective function measures profit; it is assumed that every piece stocked will be sold. Constraint 1 measures display space in units, constraint 2 measures time to set up the display in minutes. Constraints 3 and 4 are marketing restrictions.

LINEAR PROGRAMMING PROBLEM

MAX 100X1+120X2+150X3+125X4

S.T.

1) X1+2X2+2X3+2X4<108

2) 3X1+5X2+X4<120

3) X1+X3<25

4) X2+X3+X4>50

OPTIMAL SOLUTION

Objective Function Value = 7475.000

Variable

Value

Reduced Cost

X1

8.000

0.000

X2

0.000

5.000

X3

17.000

0.000

X4

33.000

0.000

Constraint

Slack/Surplus

Dual Price

1

0.000

75.000

2

63.000

    0.000

3

0.000

25.000

4

0.000

25.000

OBJECTIVE COEFFICIENT RANGES

Variable

Lower Limit

Current Value

Upper Limit

X1

87.500

100.000

No Upper Limit

X2

No Lower Limit

120.000

125.000

X3

125.000

150.000

162.500

X4

120.000

125.000

150.000

RIGHT HAND SIDE RANGES

Constraint

Lower Limit

Current Value

Upper Limit

1

100.000

108.000

123.750

2

57.000

120.000

No Upper Limit

3

    8.000

25.000

58.000

4

41.500

50.000

54.000

  

Use the output to answer the question.

By how much will the second marketing restriction be exceeded?

NB: You have to use spreadsheet to solve this problem. Type the answer in the space provided below. In your answer just type the number, without any symbols (like $) or comma (,) etc.

If the answer is just a whole number just type whole number. For example, if you want to answer 8 cars. Just type 8.

If the answer is not a whole number type two digits after the decimal points. For example, if your answer is $345,000.654 type 345000.65.

1) X1+2X2+2X3+2X4<108

2) 3X1+5X2+X4<120

3) X1+X3<25

4) X2+X3+X4>50

Explanation / Answer

In slack/surplus and dual price output table, the slack/surplus for the 4th constraint is zero, this means this constraint is binding constraint and is completely utilized.

Thus, the second marketing restriction is exceeding by zero amount.

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