The Bijou Theater in Hermosa Beach, California, shows vintage movies. Customers
ID: 459351 • Letter: T
Question
The Bijou Theater in Hermosa Beach, California, shows vintage movies. Customers arrive at the theater line at the rate of 102 per hour. The ticket seller averages 30 seconds per customer, which includes placing validation stamps on customers' parking lot receipts and punching their frequent watcher cards. (Because of these added services, many customers don't get in until after the feature has started.) Use Exhibit_7.12. a. What is the average customer time in the system? (Do not round intermediate calculations. Round your answer to 2 decimal places.) Average customer time minutes b. What would be the customer time in the system if a second ticket taker doing nothing but validations and card punching, is appointed thereby cutting the average service time to 20 seconds? (Do not round intermediate calculations. Round your answer to 2 decimal places.) Customer time seconds c. What would be the customer time in the system if a second window was opened with each server doing all three tasks? (Do not round intermediate calculations. Round your answer to 2 decimal places.) Customer time seconds
Explanation / Answer
Average customer time in the system = 1/(µ-) = 1/(120-102) = 0.0556 hours = 0.0556*60 = 3.33 minutes
Average customer time in the system = 1/(µ-) = 1/(180-102) = 0.128 hours = 0.128*60 = 0.77 minutes
ANSWER: customer waiting time in system = 0.0102 hour = 0.0102*3600 = 36.61 seconds
a
b
c
Inputs
Arrival rate
=
102
102
102
Service rate
=
120
180
120
Number of identical servers (c)
c
=
1
1
2
Operating Characteristics
Average Utilization rate of server
= /
85.0%
56.7%
/cµ =
42.5%
Probability of NO customers in system
P0
= 1-
15.0%
43.3%
P0 =
40.4%
Average number of customers in system
L
=/(1-)
5.6667
1.3077
Lq +/µ =
1.0374
Average time in system
W
= L/
0.0556
0.0128
L/ =
0.0102
a
b
c
Inputs
Arrival rate
=
102
102
102
Service rate
=
120
180
120
Number of identical servers (c)
c
=
1
1
2
Operating Characteristics
Average Utilization rate of server
= /
85.0%
56.7%
/cµ =
42.5%
Probability of NO customers in system
P0
= 1-
15.0%
43.3%
P0 =
40.4%
Average number of customers in system
L
=/(1-)
5.6667
1.3077
Lq +/µ =
1.0374
Average time in system
W
= L/
0.0556
0.0128
L/ =
0.0102
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.